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\title{电子学基础——第二次仿真作业}
\author{LXQ}
\date{2019.11.22}

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\begin{document}

\maketitle

\paragraph{1} Using ac analysis in Multisim, plot the frequency response of the circuit depicted in Fig. 8-68.

\paragraph{答}
仿真电路图以及仿真所得到的幅频和相频特性曲线如图所示。由图可知，在低频（$1\megahertz$以下）时，电路的作用为移相器，且所移动相位为$\pi$。当频率逐渐增高，电路的移相作用趋于$0$。

\begin{figure}[!htb]
    \centering
    \begin{minipage}[t]{0.346\textwidth}
    \centering
    \includegraphics[width=1\textwidth]{cir.png}
    \caption*{(1) 电路图}
    \end{minipage}
    \\
    \begin{minipage}[t]{0.453\textwidth}
    \centering
    \includegraphics[width=1\textwidth]{res.png}
    \caption*{(2) 仿真结果}
    \end{minipage}
    \caption*{Figure 1}
\end{figure}    

\end{document}